Physics - Paper 1

studied byStudied by 0 people
0.0(0)
get a hint
hint

Newton's Third Law

1 / 463

Tags and Description

464 Terms

1

Newton's Third Law

If object A exerts a force on object B, then object B exerts an equal but opposite force on object A

New cards
2

Newton's Third Law pairs

Example: An object exerts a weight of 50N onto the earth. The third law pair would be that the earth would exert a NCF of 50N on the object

New cards
3

Conditions for Newton's Third Law Pairs to be true

  • Two Different Forces

  • Act on the same line

  • Same magnitude

  • Different objects

  • same time

New cards
4

Potential Divider equation

Vout/Vin = R1/R1+R2

New cards
5

Potential Dividers and thermistors

If a thermistor is used as R1, as temperature decreases resistance increases and thus Vout increases as they are proportional, this can be used as a heating system to turn it on if it gets cold enough

New cards
6

Potential Dividers and LDRs

If a LDR is used as R1, as light decreases resistance increases and thus Vout increases as they are proportional, this can be used for street lights to be turned on as light decreases

New cards
7

Thermistor

a resistor whose resistance depends on the temperature of the thermistor

As temperature decreases resistance increases

New cards
8

LDR

Light dependent resistor

As light increases resistance decreases

New cards
9

Rheostat

When a variable resistor is used to control current

New cards
10

Variable Resistor

A resistor whose value can be varied between its minimum and maximum values.

New cards
11

Variable Resistors and Potential Divider Uses

A variable resistor can act as a potential divider to act as a continuous slider to increases or decrease Vout. This can be used as a dimmer switch

New cards
12

Magnetic Flux Density

a measure of the strength of the magnetic field.

How densely packed lines of flux are equates to how strong a field is

Measures in Tesla T

New cards
13

Magnetic Flux

The total number magnetic field lines that pass through a surface

= magnetic flux density x Area

New cards
14

Magnetic Flux Linkage

The product of the magnetic flux and the number of turns in a given coil = Number of coils x magnetic flux

New cards
15

Equations of motion

v = u + at

s = 1/2(v+u)t

s = ut + 1/2at^2

v^2 = u^2 + 2as

New cards
16

Equation of motion for velocity

v = u + at

New cards
17

Equation of motion for distance

s = 1/2(v+u)t

s = ut + 1/2at^2

New cards
18

Equation of motion for velocity squared

v^2 = u^2 + 2as

New cards
19

Equation for an magnetic field on a wire

F = BIL

F = Force, B = Magnetic field strength (density), I = Current, L = Length

New cards
20

Equation for a magnetic field on a wire not at 90 degrees to the field

F = BILsin(angle)

Angle at 90 degrees should just use F = BIL as sin90 = 1 therefore cos component will not affect the force

Angle at 90 degrees should just use F = BIL as sin90 = 1 therefore cos component will not affect the force

New cards
21

Equation for a magnetic field on a moving charge

F = BQV

F = Force, B = Magnetic field strength (density), Q = charge, V = velocity

New cards
22

Equation for a magnetic field of a moving charge not at 90 degrees to the field

F = BQVsin(angle)

Angle at 90 degrees should just use F = BIL as sin90 = 1 therefore cos component will not affect the force

Angle at 0 degrees will be 0 as sin0 = 0

New cards
23

Fleming's Left Hand Rule

First Finger = Field

seCond finger = Current

thuMb = Motion

New cards
24

Relativistic Effects

Only when objects approach the speed of light do our observations begin to depart measurably from the predictions of Newtonian Physics

New cards
25

Muon Decay and Relativistic Effects

Muons are created a few kilometers above the earth yet for the time they should take to get here they would decay before they hit the surface

But they do hit the surface, this is due to relativistic effects as muons are going close to the speed of light

New cards
26

The doppler Effect Model Answer

As something that is moving is giving out a wave its frequency can change as it is being compressed by the moving object and therefore to a relative observer the frequency appears higher

New cards
27

Cosmological Red Shift Model Answer

As the universe expands, galaxies are moving away from us the relative observer. The light these galaxies give off it also redshifted so that its wavelength increases

New cards
28

Cosmological Redshift Equation

z = ∆Wavelength/Wavelength = Velocity/Speed of light

New cards
29

Total Internal Reflection Model Answer

If the angle of incidence is greater than the critical angle no light is refracted out of the medium and all of the light is reflected back into the medium. All light has been totally internally reflected

New cards
30

Critical Angle

The largest angle as which refraction out of a denser medium is possible

New cards
31

Critical Angle Equation

n = 1/sinc

n = Refractive Index, c = critical angle

New cards
32

How to measure the refractive index of a material?

Measure the angle of incidence of a light ray in a material and then the angle of refraction

use sin1/sinr = n to find the refractive index

New cards
33

How to predict whether total internal reflection will happen?

If the angle of incidence as it meets the surface is less than the critical angle, the ray will be refracted into the medium, but some can get reflected, this is know as partial internal reflection

Increasing this will go to total internal reflection.

New cards
34

How to add vector components?

Use a protractor to ensure correct angle

Place each vector head to tail

Join the first tail and final head together to get the resultant

New cards
35

Resolving vectors

Place vectors together

For a right angle triangle sides can be calculated using Pythagoras

Other triangles can be calculated using cosine

New cards
36

Internal Resistance

resistance inside the source of electrical energy - loss of PD per unit current in the source when current passes through it

New cards
37

Electromotive force

The electrical potential energy transferred from other forms, per coulomb of change that passes through the source

New cards
38

Energy transfer EMF equation

Work Done = Charge x emf

New cards
39

Emf Equations

E = V + IR

E = IR + Ir

E = I(R + r)

(E = emf, V = Voltage, I = Current, R = resistance)

New cards
40

Lost Volts

The potential difference across the internal resistor of a source of e.m.f.

emf = V + lost volts

New cards
41

The difference between emf and pd

emf is the energy transferred from chemical to electrical

pd is the energy transferred from electrical to other forms e.g. light, heat

New cards
42

emf is transfered from other forms where as pd transfers to other forms

New cards
43

How to increase induced emf

  • Use a stronger magnet

New cards
44
  • use a coil with more turns

New cards
45
  • use a coil with greater cross sectional area

New cards
46
  • Make relative movement between magnet and conductor faster

New cards
47

Baryon

A hadron consisting of three quarks

New cards
48

Meson

A hadron consisting of a quark and an antiquark

New cards
49

Lepton

An elementary particle that have no internal structre

New cards
50

Hadron

A particle made up of quarks

New cards
51

Lepton Examples

1st gen electron

New cards
52

2nd gen muon

New cards
53

3rd gen tau

New cards
54
New cards
55

Increasing 1-3

New cards
56

Examples of mesons

pion, kaon

New cards
57

Examples of baryons

protons and neutrons

New cards
58

An object thrown off a cliff time taken to reach ground

Use suvat remembering u is 0

New cards
59

An object thrown off a cliff distance it lands from the foot of the cliff

Horizontal distance = horizontal velocity x time of flight

New cards
60
New cards
61

Horizontal velocity is given

New cards
62

Time may be given or worked out earlier using suvat

New cards
63

An object thrown off a cliff magnitude of final velocity

Vertical Velocity = u + at

New cards
64

Horizontal Velocity is given in the question

New cards
65

Use Pythagoras to find resultant

New cards
66

An object being hit off the ground at an angle time in air

Consider vertical velocity = 0

New cards
67

Consider vertical component of initial launch

New cards
68

using SOHCAHTOA

New cards
69

Know acceleration is negative and dependant on the planet

New cards
70
New cards
71

Use suvant to find t

New cards
72

Double it as this motion is parabolic and thus half of the time

New cards
73

An object being hit off the ground at an angle horizontal distance travelled

Work out horizontal component of inital velocity

New cards
74
New cards
75

Use d = horizontal velocity x time

New cards
76

Effect of friction on projectiles vertical motion

Upwards gravity and friction work together to slow down projectile

New cards
77

Downwards friction goes against gravity slowing it

New cards
78

Effect of friction on projectiles horizontal motion

Drag forces oppose the motion, leading to horizontal deceleration

New cards
79

Change in resistance with temperature model answer

  • Metals contain large numbers of free electrons

New cards
80
  • As these electrons move through the metal lattice they collide with vibrating metal ions

New cards
81
  • These collisions oppose the flow of electrons so the metal has a set resistance

New cards
82
  • When temperature increases ions vibrate faster and make it more difficult for electrons to pass through the lattice increasing resistance futher

New cards
83

Faraday's Law

The magnitude of the induced emf is directly proportional to the rate of change of flux linkage

New cards
84

Faraday's Equation

emf = coils x change in flux linakge / time taken

New cards
85
New cards
86

Change in flux linkage can be calculated by multiplying the field strength and the area

New cards
87

Lenz's Law

The direction of an induced current is such that it will try to oppose the change in flux that is producing it

New cards
88

Lenz's Equation

Is like faraday's but adds a negative sign

New cards
89
New cards
90

emf = -coils x change in flux linakge / time taken

New cards
91

An emf is induced

When there is relative movement between a magnet and a coil

New cards
92

Dropping a bar magnet through a coil

As the magnet enter the coil the flux linkage of the coil increases and an emf is induced

New cards
93
New cards
94

As the magnet falls right in the middle of the coil there is 0 flux linkage and no emf induced

New cards
95
New cards
96

As the magnet falls out of the coil the flux linkage decreases and emf is induced in the opposite direction

New cards
97
New cards
98

Emf is equal to a area strip under the graph

New cards
99
New cards
100

The second dip is narrower as the magnet is accelerating due to gravity

New cards

Explore top notes

note Note
studied byStudied by 24 people
Updated ... ago
5.0 Stars(2)
note Note
studied byStudied by 32 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 14 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 13 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 16 people
Updated ... ago
4.5 Stars(2)
note Note
studied byStudied by 51 people
Updated ... ago
4.5 Stars(4)
note Note
studied byStudied by 3 people
Updated ... ago
5.0 Stars(1)
note Note
studied byStudied by 33238 people
Updated ... ago
4.9 Stars(62)

Explore top flashcards

flashcards Flashcard101 terms
studied byStudied by 5 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard34 terms
studied byStudied by 9 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard33 terms
studied byStudied by 7 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard45 terms
studied byStudied by 7 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard76 terms
studied byStudied by 41 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard59 terms
studied byStudied by 2 people
Updated ... ago
5.0 Stars(1)
flashcards Flashcard44 terms
studied byStudied by 10 people
Updated ... ago
4.0 Stars(1)
flashcards Flashcard46 terms
studied byStudied by 215 people
Updated ... ago
5.0 Stars(2)